-98p^2+2=0

Solution for -98p^2+2=0 equation:

-98p^2+2=0

a = -98; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-98)·2
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*-98}=\frac{-28}{-196}
=1/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*-98}=\frac{28}{-196}
=-1/7
$